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  1. How much zeros has the number $1000!$ at the end?

    May 13, 2014 · 1 If a number ends with n n zeros than it is divisible by 10n 10 n, that is 2n5n 2 n 5 n. A factorial clearly has more 2 2 s than 5 5 s in its factorization so you only need to count how many 5 5 …

  2. probability - 1/1000 chance of a reaction. If you do the action 1000 ...

    A hypothetical example: You have a 1/1000 chance of being hit by a bus when crossing the street. However, if you perform the action of crossing the street 1000 times, then your chance of being ...

  3. Creating arithmetic expression equal to 1000 using exactly eight 8's ...

    I would like to find all the expressions that can be created using nothing but arithmetic operators, exactly eight $8$'s, and parentheses. Here are the seven solutions I've found (on the Internet)...

  4. terminology - What do you call numbers such as $100, 200, 500, 1000 ...

    What do you call numbers such as $100, 200, 500, 1000, 10000, 50000$ as opposed to $370, 14, 4500, 59000$ Ask Question Asked 13 years, 11 months ago Modified 9 years, 7 months ago

  5. definition - What is the smallest binary number of $4$ bit? Is it ...

    Sep 29, 2024 · In pure math, the correct answer is $ (1000)_2$. Here's why. Firstly, we have to understand that the leading zeros at any number system has no value likewise decimal. Let's …

  6. algebra precalculus - Which is greater: $1000^ {1000}$ or $1001^ {999 ...

    The way you're getting your bounds isn't a useful way to do things. You've picked the two very smallest terms of the expression to add together; on the other end of the binomial expansion, you have terms …

  7. Why is 1 cubic meter 1000 liters? - Mathematics Stack Exchange

    Mar 7, 2015 · 0 Can anyone explain why $1\ \mathrm {m}^3$ is $1000$ liters? I just don't get it. 1 cubic meter is $1\times 1\times1$ meter. A cube. It has units $\mathrm {m}^3$. A liter is liquid amount …

  8. algebra precalculus - Multiple-choice: sum of primes below $1000 ...

    Jan 30, 2017 · Given that there are $168$ primes below $1000$. Then the sum of all primes below 1000 is (a) $11555$ (b) $76127$ (c) $57298$ (d) $81722$ My attempt to solve it: We know that below …

  9. modular arithmetic - How many numbers are there between $0$ and …

    How many numbers are there between $0$ and $1000$ which on division by $2, 4, 6, 8$ leave remainders $1, 3, 5, 7$ resp? What I did:- Observe the difference between divisor and remainder. $2 …

  10. combinatorics - Probability of winning a prize in a raffle ...

    You'll be surprised. The correct probability of winning at least one ticket is around $0.2242$. Assuming exactly one prize is given, your answer of $\frac {1} {160}$ is the probability of winning is correct. …